8x^2+28x+2=0

Solution for 8x^2+28x+2=0 equation:

8x^2+28x+2=0

a = 8; b = 28; c = +2;
Δ = b2-4ac
Δ = 282-4·8·2
Δ = 720
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{720}=\sqrt{144*5}=\sqrt{144}*\sqrt{5}=12\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-12\sqrt{5}}{2*8}=\frac{-28-12\sqrt{5}}{16}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+12\sqrt{5}}{2*8}=\frac{-28+12\sqrt{5}}{16}
$